User:Alemagno12/Six Trials of Formal Analysis: Difference between revisions
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, 10 months agosorry for the edit spam, I haven't edited a wiki page in ages and I keep making mistakes x_x
Alemagno12 (talk | contribs) (Created page with "I've been a googologist/apeirologist for 9 years now, and have made many analyses ever since. However, all of my analyses have been heuristic guesses and analysis tables; I've since learned how to do formal proofs and I've tried to make formal analyses a few times now, but I've always lost motivation pretty quickly, leaving only a draft or an unfinished proof somewhere in the Googology Discord (see e.g |this or File:Unfinished proof 2.jp...") |
Alemagno12 (talk | contribs) m (sorry for the edit spam, I haven't edited a wiki page in ages and I keep making mistakes x_x) |
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I've been a googologist/apeirologist for 9 years now, and have made many analyses ever since. However, all of my analyses have been heuristic guesses and analysis tables; I've since learned how to do formal proofs and I've tried to make formal analyses a few times now, but I've always lost motivation pretty quickly, leaving only a draft or an unfinished proof somewhere in the Googology Discord (see e.g [[:File:Unfinished proof 1.
So I'm proposing myself six analysis challenges to become more familiar with formal analyses, which will hopefully motivate me to do more of them in the future:
1. HPrSS v1 by Yukito vs HPrSS v3 by Yukito (expected correspondence: lim(HPrSSv1) = HPrSSv3(0,3,5,2,5,7,4,7,9,5), from a [[File:HPrSS claim.jpg||2018 heuristic analysis]])▼
2. HPrSS v2 by Yukito vs HPrSS v3 by Yukito (expected correspondence: lim(HPrSSv2) = HPrSSv3(0,3,5,8,10,4), from a [[File:HPrSS claim.jpg||2018 heuristic analysis]])▼
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3. [TBA] vs [TBA]▼
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4. [TBA] vs [TBA]▼
5. Dropping Hydra (x = 1) by Hyp cos vs BM2.3 by Bashicu and koteitan (expected correspondence: lim(Dropping Hydra) = BM2.3(0,0,0)(1,1,1)(2,2,0))▼
6. Dropping Hydra (full) by Hyp cos vs BM2.3 by Bashicu and koteitan (expected correspondence: lim(Dropping Hydra(x+1)) = BM2.3(0,0,0)(1,1,1)(2,2,1)<sup>x</sup>(2,2,0))▼
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